document.write( "Question 60453This question is from textbook college algebra
\n" );
document.write( ": 9x-5x^2=-2\r
\n" );
document.write( "\n" );
document.write( "2x^2-3x=x^2+18\r
\n" );
document.write( "\n" );
document.write( "15x^2+x=2\r
\n" );
document.write( "\n" );
document.write( "x^2-6x+9=-16 \n" );
document.write( "
Algebra.Com's Answer #41526 by asha(30)![]() ![]() ![]() You can put this solution on YOUR website! 9x-5x^2=-2 \n" ); document.write( " 5x^2-9x-2=0 taking all the terms to the rightside \n" ); document.write( "5x^2-10x+x-2=0 by splitting the middle term so that sum is-9 product is-10 \n" ); document.write( "5x(x-2)+1(x-2)=0 taking common terms \n" ); document.write( "(5x+1)(x-2)=0 \n" ); document.write( "x=-1/5 or x=2 is the answer.\r \n" ); document.write( "\n" ); document.write( "ii)2x^2-3x=x^2+18 \n" ); document.write( " 2x^2-3x-x^2-18=0 x^2-3x-18=0 \n" ); document.write( "x^2-6x+3x-18=0 splitting the middle term so that sum is-3 and product is-18 \n" ); document.write( "x(x-6)+3(x-6)=0taking common terms \n" ); document.write( "(x+3)(x-6)=0 \n" ); document.write( "x=-3 or x=6 is the answer.\r \n" ); document.write( "\n" ); document.write( "iii)15x^2 +x=2 15x^2+x-2=0 taking all the terms to l.h.s. \n" ); document.write( "15x^2 +6x-5x-2=0 3x(5x=2)-1(5x+2)=0 productis -2 and sum is1 \n" ); document.write( "(3x-1)(5x+2)=0 \n" ); document.write( "x=1/3 or x=-2/5 is the answer.\r \n" ); document.write( "\n" ); document.write( "iv)x^2-6x+9=16 taking all teh terms to l.h.s. we get \n" ); document.write( " x^2-6x+9-16=0 x^2-6x-7=0 \n" ); document.write( " x^2-7x+x-7=0 product is -7 and sum is-6 \n" ); document.write( " x(x-7)+1(x-7)=0 \n" ); document.write( " (x-7)(x+1)=0 \n" ); document.write( " x=-1or x=7 is the answer.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |