document.write( "Question 667884: I try doing but I got stuck on the last part. How do you solve ((3x^2)(6x^-1)^2/(16y^3)(5y^-1)). I got 108x^0/80y^2 but you have to simplify it which is 27/20y^2 but I do not understand how they got the 27 from. \n" ); document.write( "
Algebra.Com's Answer #415255 by MathTherapy(10552)\"\" \"About 
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I try doing but I got stuck on the last part. How do you solve ((3x^2)(6x^-1)^2/(16y^3)(5y^-1)). I got 108x^0/80y^2 but you have to simplify it which is 27/20y^2 but I do not understand how they got the 27 from.\r
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\n" ); document.write( "\n" ); document.write( "You're correct up to this point: \"108x%5E0%2F80y%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"108x%5E0\" = \"108+%2A+x%5E0\" = 108 * 1 ------ Anything to the \"0\" power = 1\r
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\n" ); document.write( "\n" ); document.write( "We now have: \"108%2F80y%5E2\", which when simplified results in: \"highlight_green%2827%2F20y%5E2%29\" --- Dividing numerator and denominator by GCF, 4\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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