document.write( "Question 667748: At what rate must motorist A travel to overtake motorist B who is traveling at a rate 20 miles/hour slower if A starts two hours after B and wishes to overtake B in 4 hours? \n" ); document.write( "
Algebra.Com's Answer #415250 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! At what rate must motorist A travel to overtake motorist B who is traveling at a rate 20 miles/hour slower if A starts two hours after B and wishes to overtake B in 4 hours? \n" ); document.write( ": \n" ); document.write( "let r = the rate required by A to overtake B \n" ); document.write( "Then \n" ); document.write( "(r-20) = the rate of B \n" ); document.write( ": \n" ); document.write( "Travel time of A is 4 hrs, travel time of B is 6 hrs \n" ); document.write( ": \n" ); document.write( "Write a distance equation, both will have traveled the same dist when A catches B \n" ); document.write( "dist = speed*time \n" ); document.write( ": \n" ); document.write( "4r = 6(r-20) \n" ); document.write( "4r = 6r - 120 \n" ); document.write( "120 = 6r - 4r \n" ); document.write( "r = 120/2 \n" ); document.write( "r = 60 mph, to overtake in 4 hrs \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this by finding the distance each traveled, should be equal \n" ); document.write( "4(60) = 240 mi \n" ); document.write( "6(40) = 240 mi \n" ); document.write( " |