document.write( "Question 60330: can you show me how can i make this out of linear inequalities by graphing.
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document.write( " x – 3y > 6
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document.write( " 3x + 2y > 12
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Algebra.Com's Answer #41524 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! x – 3y > 6 [Re-write in the slope-intercept format by solving for y] \n" ); document.write( "-3y>-x+6 \n" ); document.write( "-3y/-3<-x/-3+6/-3 [Switch the sign when multiplying or dividing by a negative number] \n" ); document.write( ". \n" ); document.write( "y<1/3x-2 \n" ); document.write( "The y-intercept is (0, -2) \n" ); document.write( "The x-intercept is (6, 0) \n" ); document.write( "The slope is (1/3) \n" ); document.write( "Graphing: Draw a dashed boundary line and shade all of the points below the dashed line. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( "3x + 2y > 12 [Re-write in the slope-intercept format by solving for y] \n" ); document.write( "2y>-3x+12 \n" ); document.write( "2y/2>-3/2x+12/2 \n" ); document.write( "y>-3/2x+6 \n" ); document.write( "The y-intercept is (0,6) \n" ); document.write( "The x-intercept is (4, 0)\r \n" ); document.write( "\n" ); document.write( "Graphing: Draw a dashed line and shade all of the points above the dahsed line. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ". \n" ); document.write( "Graph both lines together to get the area of overlap. The area of overlap represents all of the points that the two lines have in common. \n" ); document.write( ".\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |