document.write( "Question 667827: The physical fitness of a patient is often measured by the patient’s maximum oxygen uptake (ml/kg). The mean maximum oxygen uptake for cardiac patients who regularly participate in sports or exercise programs is 24.1 ml/kg and the standard deviation is 6.30 ml/kg. Maximum oxygen uptake measurements have a Normal distribution.
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\n" ); document.write( "b) What is the probability that a cardiac patient who regularly participates in sports or exercise programs has a maximum oxygen uptake between 18 ml/kg and 31 ml/kg?
\n" ); document.write( "c) What is the probability that a cardiac patient who regularly participates in sports or exercise programs has a maximum oxygen uptake of 10.5 ml/kg or lower?
\n" ); document.write( "d) Consider a cardiac patient with a maximum oxygen uptake of 10.5 ml/kg. Is it likely that this patient regularly participates in sports or exercise programs?
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Algebra.Com's Answer #415210 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "μ = 24.1  and  σ = 6.3
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document.write( "I.Find the corresponding z-values: z = (x-24.1)/6.3 
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document.write( "II.  Use that z-value to calculate the P-value asked for
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document.write( "corresponding P-value will be the portion of under the standard normal curve
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document.write( "to the LEFT of the z-value
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document.write( "a) P(x≥20) = 1 - P(z-value)
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document.write( "b)P( 18< x< 31) = P(z=7.1/6.3)- P(z = -6.1/6.3)  
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document.write( "c) P(x ≤ 10.5) = P(z = -13.6/6.3)
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document.write( "d) z-value =  -2.1587,  most likely NOT :)
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document.write( "Important to Understand z -values as they relate to the Standard Normal curve:
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document.write( "Below:  z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.  
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document.write( "Note: z = 0 , 50% of the area under the curve is to the left and 50%  to the right
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