document.write( "Question 667805: Input in standard form the equation of the given line.\r
\n" ); document.write( "\n" ); document.write( "The line that passes through (-1, -3) and (2, 1)
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Algebra.Com's Answer #415179 by swincher4391(1107)\"\" \"About 
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Step 1: Find the slope of the line that passes through those two lines. \r
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\n" ); document.write( "\n" ); document.write( "Step 2: Put into point slope form. Choose either point. We'll choose (2,1).\r
\n" ); document.write( "\n" ); document.write( "\"%28y-y1%29+=+m%28x-x1%29\"
\n" ); document.write( "\"%28y-1%29+=+%284%2F3%29%28x-2%29\"
\n" ); document.write( "\"y-1+=+%284%2F3%29x+-+8%2F3\"
\n" ); document.write( "Since we know we're going into standard form Ax+Bx=C where A,B are integers, we know we cannot have fractional coefficients of x or y. (Since fractions are rational not integers) So, to make life easy, let's multiply the entire equation by 3 to get rid of the fractions.\r
\n" ); document.write( "\n" ); document.write( "\"3%28y-1%29+=+3%28%284%2F3%29x-8%2F3%29%29\"
\n" ); document.write( "\"3%28y-1%29+=+4x-8\"
\n" ); document.write( "\"3y-3+=+4x+-8\"\r
\n" ); document.write( "\n" ); document.write( "\"-4x+%2B+3y+=+-5\"
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