document.write( "Question 60446This question is from textbook alegbra concepts and applications
\n" ); document.write( ": Find the distance between the points\r
\n" ); document.write( "\n" ); document.write( "(0,2) and ( 3,6) \n" ); document.write( "

Algebra.Com's Answer #41514 by josmiceli(19441) $\"\"$ $\"About$

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This is geometry.
\n" ); document.write( "Remeber (x,y) is always how points appear written this way.
\n" ); document.write( "You've got (x1 , y1) and (x2 , y2)
\n" ); document.write( "The horizontal distance is x2 - x1
\n" ); document.write( "The vertical distance is y2 - y1.
\n" ); document.write( "The points are (0,2) and (3,6)
\n" ); document.write( "x2 - x1 = 3 - 0
\n" ); document.write( "x2 - x1 = 3
\n" ); document.write( "y2 - y1 = 6 - 2
\n" ); document.write( "y2 - y1 = 4
\n" ); document.write( "Now you need the formula for the hypotenuse of a right triange
\n" ); document.write( " $\"l%5E2+=+x%5E2+%2B+y%5E2\"$ where l,x, and y are all distances (not points)
\n" ); document.write( " $\"l%5E2+=+3%5E2+%2B+4%5E2\"$ read: length between points squared equals
\n" ); document.write( "the x length squared plus y length squared
\n" ); document.write( " $\"l%5E2+=+9+%2B+16\"$
\n" ); document.write( " $\"l%5E2+=+25\"$
\n" ); document.write( " $\"l+=+sqrt%2825%29\"$
\n" ); document.write( " $\"l+=+5\"$ answer \n" ); document.write( "

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