document.write( "Question 667707: A man invested part of Php 15,000 at 12 percent and the remainder at 8 percent. If his annual income from the investment is Php 1,456, How much does he have invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #415137 by mananth(16946)\"\" \"About 
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Part I 8.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 12.00% per annum ------------ Amount invested = y =
\n" ); document.write( " 15000
\n" ); document.write( "Interest----- 1456
\n" ); document.write( "
\n" ); document.write( "Part I 8.00% per annum ---x
\n" ); document.write( "Part II 12.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 15000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "8.00% x + 12.00% y= 1456
\n" ); document.write( "Multiply by 2
\n" ); document.write( "8 x + 12 y= 145600.00 --------2
\n" ); document.write( "Multiply (1) by -8
\n" ); document.write( "we get
\n" ); document.write( "-8 x -8 y= -120000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 4 y= 25600
\n" ); document.write( "divide by 4
\n" ); document.write( " y = 6400
\n" ); document.write( "Part I 8.00% php 8600
\n" ); document.write( "Part II 12.00% php 6400
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "8600 --------- 8.00% ------- 688.00
\n" ); document.write( "6400 ------------- 12.00% ------- 768.00
\n" ); document.write( "Total -------------------- 1456.00
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\n" ); document.write( "m.ananth@hotmail.ca
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