document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=667729>Question 667729</A>: <I><SPAN STYLE=\"word-break: break-all;\"> After robbing a bank in Dodge City, a robber gallops off at 14 mi/h. 10 minutes later, the marshall leaves to pursue the robber at 15 mi/h. How long (in hours) does it take the marshall to catch up to the robber?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #415134 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=415134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In such problems you have to find the catchup distance and the catch up speed\r<BR>\n" );
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document.write( "Robber speed = 14 mph\r<BR>\n" );
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document.write( "he has a lead time of 10 minutes. = 1/6 hour.\r<BR>\n" );
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document.write( "when Marshall starts the robber is 1/6 * 14 = 14/6-> 7/3 miles away\r<BR>\n" );
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document.write( "Marshall speed = 15 mph\r<BR>\n" );
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document.write( "catchup speed = 15-14 = 1mph\r<BR>\n" );
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document.write( "time = d/r\r<BR>\n" );
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document.write( "t= (7/3) / 1\r<BR>\n" );
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document.write( "so Marshall will take 7/3 hours to catch him<BR>\n" );
document.write( "= 2 hours and 20 minutes </SPAN>\n" );
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