document.write( "Question 667692: Wilma drove at an average speed of 40 mi/h from her home in City A to visit her sister in City B. She stayed in City B 15 hours, and on the trip back averaged 50 mi/h. She returned home 48 hours after leaving. How many miles is City A from City B \n" ); document.write( "
Algebra.Com's Answer #415131 by mananth(16946)\"\" \"About 
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Let distance from city A to city B be x miles\r
\n" ); document.write( "\n" ); document.write( "speed forward = 40 mph
\n" ); document.write( "return speed = 50 mph\r
\n" ); document.write( "\n" ); document.write( "total time 48 hours
\n" ); document.write( "less 15 hours at sister's place
\n" ); document.write( "48-15=33 hours\r
\n" ); document.write( "\n" ); document.write( "Time forward + time return = 33\r
\n" ); document.write( "\n" ); document.write( "time = d/r\r
\n" ); document.write( "\n" ); document.write( "\"x%2F40+%2B+x%2F50+=+33\"\r
\n" ); document.write( "\n" ); document.write( "LCD = 200\r
\n" ); document.write( "\n" ); document.write( "multiply equation by 200\r
\n" ); document.write( "\n" ); document.write( "5x+4x=33*200\r
\n" ); document.write( "\n" ); document.write( "9x= 6600
\n" ); document.write( "x= 6600/9
\n" ); document.write( "733.33 miles is the distance from A to B\r
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