document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=667650>Question 667650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can two angles of a kite be as follows? Explain.<BR>\n" );
document.write( "(opposite and complementary) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #415129 by </B><A HREF=/tutors/aboutme.mpl?userid=MathLover1><B>MathLover1(20854)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathLover1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathLover1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=415129\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> by definition, the opposite angles at the endpoints of the cross diagonal are congruent\r<BR>\n" );
document.write( "\n" );
document.write( "when a kite's opposite angles are both <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90 ALIGN=MIDDLE  ALT=\"90\"   DISABLED_style= \"max-width:90%; height:auto;\" >° (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90%2B+90+=+180 ALIGN=MIDDLE  ALT=\"90%2B+90+=+180\"   DISABLED_style= \"max-width:90%; height:auto;\" >), then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=yes ALIGN=MIDDLE  ALT=\"yes\"   DISABLED_style= \"max-width:90%; height:auto;\" >, they can </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );