document.write( "Question 7516: how do i simplify a question like : 2/3(6h-1) \n" ); document.write( "

Algebra.Com's Answer #4151 by bonster(299) $\"\"$ $\"About$

You can put this solution on YOUR website!
first, multiply $\"2%2F3\"$ to both 6h and to -1\r
\n" ); document.write( "\n" ); document.write( "( $\"2%2F3\"$ )(6h)+( $\"2%2F3\"$ )(-1)
\n" ); document.write( "=4h- $\"2%2F3\"$ \n" ); document.write( "

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