document.write( "Question 667585: A car travels 200 miles in the same time it takes a car traveling 10 miles per hour slower to travel 150 miles. give the speed of each car\r
\n" ); document.write( "\n" ); document.write( "I tried to solve it like this:\r
\n" ); document.write( "\n" ); document.write( "x+200=x+150-10
\n" ); document.write( "x+200=x+140
\n" ); document.write( " -140 -140
\n" ); document.write( "----------------
\n" ); document.write( "x+60=x
\n" ); document.write( "-x -x
\n" ); document.write( "----------------
\n" ); document.write( "60=x\r
\n" ); document.write( "\n" ); document.write( "Thus, 60 mph being the speed of the first car, and 50 mph the speed of the second car.\r
\n" ); document.write( "\n" ); document.write( "That was incorrect.
\n" ); document.write( "

Algebra.Com's Answer #415098 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
A car travels 200 miles in the same time it takes a car traveling 10 miles per hour slower to travel 150 miles. give the speed of each car
\n" ); document.write( "I tried to solve it like this:
\n" ); document.write( "x+200=x+150-10
\n" ); document.write( "x+200=x+140
\n" ); document.write( "-140 -140
\n" ); document.write( "----------------
\n" ); document.write( "x+60=x
\n" ); document.write( "-x -x
\n" ); document.write( "----------------
\n" ); document.write( "60=x
\n" ); document.write( "Thus, 60 mph being the speed of the first car, and 50 mph the speed of the second car.
\n" ); document.write( "That was incorrect.
\n" ); document.write( "========================
\n" ); document.write( "d = r*t
\n" ); document.write( "t = d/r
\n" ); document.write( "--------
\n" ); document.write( "t = 200/r = 150/(r-10)
\n" ); document.write( "200*(r-10) = 150r
\n" ); document.write( "200r - 2000 = 150r
\n" ); document.write( "50r = 2000
\n" ); document.write( "r = 40 mi/hr
\n" ); document.write( "r-10 = 30 mi/hr
\n" ); document.write( "
\n" ); document.write( "
\n" );