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Well, here's a short cut that works when you're dividing two polynomials where one is a linear expression, as is (x+2). The zero value, or the value of x that would give us zero for the expression, for (x+2) would be (-2). So, what we do is we line up the -2 on the left, which should be followed by the coefficients. Hence we have the following:
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\n" ); document.write( "-2 ||....2...3...-3...4\r
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\n" ); document.write( ".............2..-1...-1...6\r
\n" ); document.write( "\n" ); document.write( "In the above, we brought the two down. Then we multiplied this by (-2) which gives us -4. We add 3 and -4, which gives us -1. Then -1 is multiplied with -2, which gives us 2. This 2 is added to -3, which gives us -1. -2 is then multiplied to -1, which gives us 2. This 2 is added to 4 which gives us 6.
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\n" ); document.write( "Now all we have to do is bring back the 'x' values and reduce the degree by 1, so we get:
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\n" ); document.write( "Hope this helped and wasn't too confusing. If it was, go to:
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\n" ); document.write( "www.purplemath.com/modules/polydiv2.htm for further help.
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\n" ); document.write( "They use a clearer method which works for more cases then the above. \n" ); document.write( "