document.write( "Question 60419: add or substitute this problem I do not know how or which to do Can you help? 10x+2y=7 y=5x+3 \n" ); document.write( "

Algebra.Com's Answer #41505 by praseena(37) $\"\"$ $\"About$

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\n" ); document.write( "10x+2y=7 and
\n" ); document.write( " y=5x+3
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\n" ); document.write( "\n" ); document.write( "y=5x+3\r
\n" ); document.write( "\n" ); document.write( "substitute the value y = 5x + 3 in the first equation\r
\n" ); document.write( "\n" ); document.write( "==> 10x + 2*(5x+3) = 7\r
\n" ); document.write( "\n" ); document.write( "10x + 2*5x + 2*3 = 7\r
\n" ); document.write( "\n" ); document.write( "10x + 10x + 6 = 7\r
\n" ); document.write( "\n" ); document.write( "20x+6 = 7\r
\n" ); document.write( "\n" ); document.write( "subtract 6 from both sides of the equation\r
\n" ); document.write( "\n" ); document.write( "==> 20x = 1\r
\n" ); document.write( "\n" ); document.write( "==> x = 1/20\r
\n" ); document.write( "\n" ); document.write( "Now substitute the value, x = 1/20 in second equation(you can substitute the value of x in first equation also)\r
\n" ); document.write( "\n" ); document.write( "==> y = 5* 1/20 + 3\r
\n" ); document.write( "\n" ); document.write( "==> y = 4 + 3
\n" ); document.write( "==> y = 7\r
\n" ); document.write( "\n" ); document.write( "so the solution of the given equations are x = 1/20 and y = 7
\n" ); document.write( "bye.
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