document.write( "Question 667406: how to factor ax^3+a \r
\n" ); document.write( "\n" ); document.write( "i factored out the \"a\" and have
\n" ); document.write( " a(x^3+1)
\n" ); document.write( "i'm using (a+b) (a^2-ab+b^2)
\n" ); document.write( "i believe it's (x+1)(x^2-1x+1)
\n" ); document.write( "I'm stuck i don't know how to move on from here.
\n" ); document.write( "Thank you :)
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Algebra.Com's Answer #415029 by lynnlo(4176)\"\" \"About 
You can put this solution on YOUR website!
ax^3+a
\n" ); document.write( "a(x^3+1)=0============solve for x
\n" ); document.write( "x^3+1=0===divide both sides by a constant to simplify the equation
\n" ); document.write( "(x+1)(x^2-x+1)=0===factor the left hand side
\n" ); document.write( "x+1=0 OR x^2-x+1=0=====split into 2 equations
\n" ); document.write( "look at the first equation,solve for X,subtract 1 from both sides
\n" ); document.write( "x=1 OR x^2-x+1=0
\n" ); document.write( "look at the second equation,solve the quadratic equation
\n" ); document.write( "by completing the square,subtract 1 from both sides x=-1 OR x^2-x=-1
\n" ); document.write( "add 1/4 to both sides======x=-1 OR x^2-x+1/4=-3/4
\n" ); document.write( "factor left side,write left hand side as a square=x=-1 OR (x-1/2)^2=-3/4
\n" ); document.write( "eliminate the exponent on left side,square root of both sides
\n" ); document.write( "x=-1 OR x-1/2= i√3/2 OR x-1/2=-1/2(i√3)
\n" ); document.write( "look at the second equation,solve for X,add 1/2 to both sides
\n" ); document.write( "x=-1 OR x=1/2+i√3/2 OR x-1/2=-1/2(i√3)
\n" ); document.write( "look at third equation,solve for X
\n" ); document.write( "add 1/2 to both sides
\n" ); document.write( "x=-1 OR x=1/2+i√3/2 OR x=1/2-i√3/2
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