document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60394>Question 60394</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 62. (x – 10)(x – 2) = -20  thanks for all your help, i really am trying </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41501 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41501\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lets first get the equation into quadratic form (ax^2+bx+c=0) and we can then apply the quadratic formula x =(-b +- sqrt( b^2-4ac ))/2a to get the two solutions.\r<BR>\n" );
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document.write( "Expanding the left side of the equation (eg., multiplying (x-10)(x-2)), we get x^2-12x+20.  We now have:\r<BR>\n" );
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document.write( "x^2-12x+20=-20, adding 20 to both sides, we have:<BR>\n" );
document.write( "x^2-12x+40=0  It's now in quadratic form and we can apply the quadratic formula to get the answer<BR>\n" );
document.write( "x=(12+-sqrt(144-160))/2 or<BR>\n" );
document.write( "x=(12+-sqrt(-16))/2 ; which yields imaginary solutions:<BR>\n" );
document.write( "x=6+2i and x=6-2i\r<BR>\n" );
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document.write( "Hope this helps-----ptaylor\r<BR>\n" );
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