document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=667348>Question 667348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an automobile radiator contains 16 liters of antifreeze and water. This mixture is 30% antifreeze. How much of this mixture should be drained and replaced with pure antifreeze so that there will be 50% antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414974 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> an automobile radiator contains 16 liters of antifreeze and water. This mixture is 30% antifreeze. How much of this mixture should be drained and replaced with pure antifreeze so that there will be 50% antifreeze?<BR>\n" );
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document.write( "let x= amt of 30% antifreeze to be drained and replaced with pure antifreeze<BR>\n" );
document.write( "16-x= amt of 30% antifreeze remaining in radiator<BR>\n" );
document.write( "30%(16-x)+100%x=50%*16<BR>\n" );
document.write( "4.8-.3x+x=8<BR>\n" );
document.write( ".7x=3.2<BR>\n" );
document.write( "x=3.2/.7<BR>\n" );
document.write( "x&#8776;4.57<BR>\n" );
document.write( "amt of 30% antifreeze to be drained and replaced with pure antifreeze=4.57 liters </SPAN>\n" );
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