document.write( "Question 667191: 2^(4y+1)-3^y=0 \n" ); document.write( "
Algebra.Com's Answer #414899 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
2^(4y+1)-3^y=0
\n" ); document.write( "---------------
\n" ); document.write( "\"2%5E%284y%2B1%29+=+3%5Ey\"
\n" ); document.write( "(4y+1)log(2) = y*log(3)
\n" ); document.write( "4y*log(2) + log(2) = y*log(3)
\n" ); document.write( "4y*log(2) - y*log(3) = -log(2)
\n" ); document.write( "y*log(16) - y*log(3) = - log(2)
\n" ); document.write( "y*(log(16) - log(3) = -log(2)
\n" ); document.write( "\"y+=+log%282%29%2F%28log%283%29+-+log%2816%29%29\"
\n" ); document.write( "\"y+=+log%282%29%2Flog%283%2F16%29\"
\n" ); document.write( " =~ -0.41407
\n" ); document.write( "
\n" ); document.write( "
\n" );