document.write( "Question 58310: can you please show me how to solve this thank you
\n" ); document.write( "(-1/3)x < 5+(2/3)x \n" ); document.write( "
Algebra.Com's Answer #41487 by jai_kos(139)\"\" \"About 
You can put this solution on YOUR website!
Given that (-1/3) x < 5+ (2/3) x\r
\n" ); document.write( "\n" ); document.write( " When we look at the questions we find that the fraction has 3 in the above equation. \r
\n" ); document.write( "\n" ); document.write( " So we multiply the above equation by 3, we get\r
\n" ); document.write( "\n" ); document.write( " (-1/3) * x * 3 < 5 * 3 + (2/3) * x * 3\r
\n" ); document.write( "\n" ); document.write( " -1 * x < 15 + 2x
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\n" ); document.write( " - x < 15 + 2x\r
\n" ); document.write( "\n" ); document.write( " Now get the all “x” on one side and numbers on the other side, we get\r
\n" ); document.write( "\n" ); document.write( " -15 < 2x + x\r
\n" ); document.write( "\n" ); document.write( " -15 < 3x\r
\n" ); document.write( "\n" ); document.write( " Now divide the above equation by 3 to get the value of “x”,\r
\n" ); document.write( "\n" ); document.write( " (-15 / 3) < x\r
\n" ); document.write( "\n" ); document.write( " -5 < x\r
\n" ); document.write( "\n" ); document.write( " Or x > -5
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