document.write( "Question 667156: A motorboat traveling with the current went 6 mi in 1 h. Against the current, it took 3 h to travel the same distance. Find the rate of the boat in calm water and the rate of the current \n" ); document.write( "
Algebra.Com's Answer #414836 by checkley79(3341)\"\" \"About 
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D=RT
\n" ); document.write( "6=R*1
\n" ); document.write( "R=6 MPH WITH THE CURRENT.\r
\n" ); document.write( "\n" ); document.write( "6=R*3
\n" ); document.write( "3R=6
\n" ); document.write( "R=6/3
\n" ); document.write( "R=2 MPH AGAINST THE CURRENT.
\n" ); document.write( "(6+2)/2= SPEED OF THE BOAT IN STILL WATER
\n" ); document.write( "8/2=4 MPH.
\n" ); document.write( "THUS THE SPEED OF THE CURRENT IS:
\n" ); document.write( "6-4=2 MPH.
\n" ); document.write( "PROOF:
\n" ); document.write( "6-2=4
\n" ); document.write( "2+2=4 \r
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