document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=667102>Question 667102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two-digit number is 14. When the digits are reversed, the new number is 36 more than the original number. What is the original number? Check your answer.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414821 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the digits be x & y,  x in the ten's place.\r<BR>\n" );
document.write( "\n" );
document.write( "x+y=14.........................(1)<BR>\n" );
document.write( "1he number is 10x+y\r<BR>\n" );
document.write( "\n" );
document.write( "reverse number is 10y+x\r<BR>\n" );
document.write( "\n" );
document.write( "10y+x= 10x+y +36<BR>\n" );
document.write( "9y-9x=36<BR>\n" );
document.write( "/9<BR>\n" );
document.write( "y-x=4..............................(2)\r<BR>\n" );
document.write( "\n" );
document.write( "add (1) & (2) <BR>\n" );
document.write( "2y=18\r<BR>\n" );
document.write( "\n" );
document.write( "/2<BR>\n" );
document.write( "y=9<BR>\n" );
document.write( "x+y =14<BR>\n" );
document.write( "so x =14-9 = 5\r<BR>\n" );
document.write( "\n" );
document.write( "The number is 59\r<BR>\n" );
document.write( "\n" );
document.write( "59+36= 95<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );