document.write( "Question 667138: After robbing a bank in Dodge City, a robber gallops off at 14 mi/h. 30 minutes later, the marshall leaves to pursue the robber at 15 mi/h. How long (in hours) does it take the marshall to catch up to the robber? \n" ); document.write( "

Algebra.Com's Answer #414815 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
The robber's head start is $\"+14%2A%281%2F2%29+=+7+\"$ miles
\n" ); document.write( "Start a stop watch when the marshall leaves town
\n" ); document.write( "Now they both ride for the same amount of time $\"+t+\"$
\n" ); document.write( "until marshall catches him
\n" ); document.write( "Let $\"+d+\"$ = distance marshall has to ride to catch him
\n" ); document.write( "robber's equation:
\n" ); document.write( "(1) $\"+d+-+7+=+14t+\"$
\n" ); document.write( "marshall's equation:
\n" ); document.write( "(2) $\"+d+=+15t+\"$
\n" ); document.write( "------------------------
\n" ); document.write( "(1) $\"+d+=+14t+%2B+7+\"$
\n" ); document.write( "By substitution:
\n" ); document.write( " $\"+14t+%2B+7+=+15t+\"$
\n" ); document.write( " $\"+t+=+7+\"$
\n" ); document.write( "It takes the marshall 7 hrs to catch robber
\n" ); document.write( "check:
\n" ); document.write( "(2) $\"+d+=+15%2A7+\"$
\n" ); document.write( "(2) $\"+d+=+105+\"$ mi
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+d+-+7+=+14%2A7+\"$
\n" ); document.write( "(1) $\"+d+=+98+%2B+7+\"$
\n" ); document.write( "(1) $\"+d+=+105+\"$ mi
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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