document.write( "Question 667075: how many liters of a 40% sulfuric acid solution should be mixed with 4 liters of a 24% sulfuric acid solution to produce 35% solution? \n" ); document.write( "
Algebra.Com's Answer #414795 by mananth(16946)![]() ![]() You can put this solution on YOUR website! -------------- percent ---------------- Amount \n" ); document.write( "Sulphuric acid I 24 ---------------- 4 liters \n" ); document.write( "sulphuric acid II 40 ---------------- x liters \n" ); document.write( "Mixture 35 ---------------- 4 + x liters \n" ); document.write( " \n" ); document.write( "24*4+40 x=35(4+x) \n" ); document.write( "96+40x =140+35 x \n" ); document.write( "40x-35 x =-96+140 \n" ); document.write( "5x=44 \n" ); document.write( "/ 5 \n" ); document.write( "x = 8.8 liters sulphuric acid II \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |