document.write( "Question 666962: 5x+3y=-11
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document.write( "2x+4y=-10 \n" );
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Algebra.Com's Answer #414745 by MatrixWoman(6)![]() ![]() You can put this solution on YOUR website! This problem can be solved by many different methods, by elimanation or the one about to show you. \n" ); document.write( "You are going to want to take the first equation times -2 \n" ); document.write( "Then take your second equation times 5 \n" ); document.write( "The reason you are doing this is because when you take -2 times 5 you will get -10 and then when you take 5 times 2 in your second equation you will get a positive 10 which will make those cancel out.(you want to cancel out the x value)\r \n" ); document.write( "\n" ); document.write( "-2(5x+3y=-11) \n" ); document.write( "5(2x+4y=-10) \n" ); document.write( "after multiplying it should look like this: \n" ); document.write( "-10x+-6y=22 \n" ); document.write( "10x+20y=-50 \n" ); document.write( "Then you simply add the two equations together \n" ); document.write( "0x+14y=-28 \n" ); document.write( "solve for y \n" ); document.write( "y=-2 \n" ); document.write( "Then pick one of your original equations and plug in your known y value \n" ); document.write( "5x+3(-2)=-11 \n" ); document.write( "5x+-6=-11 \n" ); document.write( "5x=-5 \n" ); document.write( "x=-1 \n" ); document.write( "You can then check the x and y value in the other equation to make sure it is correct. \n" ); document.write( "2(-1)+4(-2)=-10 \n" ); document.write( "and both of the values worked which means we got the right answer! :) \n" ); document.write( " \n" ); document.write( " |