document.write( "Question 666907: Larry, Curly and Mo assembled a puzzle together in 40 hours. If Curly worked twice as fast as Mo and Larry worked just as fast as Curly, then how long would it have taken Mo to assemble the puzzle alone? \n" ); document.write( "

Algebra.Com's Answer #414727 by josmiceli(19441) $\"\"$ $\"About$

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Add their rates of working to get their rate of working together
\n" ); document.write( "Let Mo's rate is ( 1 puzzle done ) / ( t hours )
\n" ); document.write( "Curly's rate is ( 2 puzzles done ) / ( t hours )
\n" ); document.write( "Larry's rate is ( 2 puzzles done ) / ( t hours }
\n" ); document.write( "---------------
\n" ); document.write( " $\"+1%2Ft+%2B+2%2Ft+%2B+2%2Ft+=+1%2F40+\"$
\n" ); document.write( "Multiply both sides by $\"+40t+\"$
\n" ); document.write( " $\"+40+%2B+80+%2B+80+=+t+\"$
\n" ); document.write( " $\"+t+=+200+\"$
\n" ); document.write( " $\"+2t+=+400+\"$
\n" ); document.write( "Mo took 200 hrs to assemble the puzzle
\n" ); document.write( "check:
\n" ); document.write( " $\"+1%2F200+%2B+2%2F200+%2B+2%2F200+=+1%2F40+\"$
\n" ); document.write( " $\"+5%2F200+=+1%2F40+\"$
\n" ); document.write( " $\"+1%2F40+=+1%2F40+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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