document.write( "Question 666802: isa wants to cover a 6-mile course in 1 hour by running part of the course and walking the rest. she also want to take a 5 inute water break. lisa runs at 8mi/h and walks at 3 mi/h. How many miles will she have to run? \n" ); document.write( "
Algebra.Com's Answer #414697 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! isa wants to cover a 6-mile course in 1 hour by running part of the course and walking the rest. \n" ); document.write( " she also want to take a 5 minute water break. \n" ); document.write( " lisa runs at 8mi/h and walks at 3 mi/h. \n" ); document.write( " How many miles will she have to run? \n" ); document.write( ": \n" ); document.write( "Let r = no. of miles to be run \n" ); document.write( "then \n" ); document.write( "(6-r) = no. of miles to be walked \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( "Change a 5 min break to 5/60 = 1/12 hr \n" ); document.write( ": \n" ); document.write( "run time + break + walk time = 1 hr \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "multiply by 24 to clear the denominators, results: \n" ); document.write( "3r + 2 + 8(6-r) = 24 \n" ); document.write( ": \n" ); document.write( "3r + 2 + 48 - 8r = 24 \n" ); document.write( "3r - 8r + 50 = 24 \n" ); document.write( "-5r = 24 - 50 \n" ); document.write( "-5r = -26 \n" ); document.write( "r = \n" ); document.write( "r = +5.2 mi running \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this, walking distance: 6 - 5.2 = .8 min \n" ); document.write( " \n" ); document.write( "use a calc, it totals 1 hr \n" ); document.write( " \n" ); document.write( " |