document.write( "Question 666709: Can you help me solve this? please i know the two points are -3 and 8 but... idk how to write it in interval notation.
\n" ); document.write( "Solve the inequality. Write the solution set in interval notation.\r
\n" ); document.write( "\n" ); document.write( "x^2 + 5x - 24 < 0
\n" ); document.write( "step by step please, thank you
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Algebra.Com's Answer #414663 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Since the inequality symbol is \"strictly less than\" rather than \"less than or equal\" your solution interval is going to be exclusive of the end points. Therefore you need to use parentheses instead of brackets to surround your interval expression. You have incorrectly identified the critical points.\r
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\n" ); document.write( "\n" ); document.write( "Set the LHS equal to zero and solve the quadratic:\r
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\n" ); document.write( "\n" ); document.write( "Hence or \r
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\n" ); document.write( "\n" ); document.write( "so if you graph those two points on the axis, you will have divided the axis into three regions: Negative infinity to -8, -8 to 3, and 3 to infinity.\r
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\n" ); document.write( "\n" ); document.write( "The three intervals are:\r
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\n" ); document.write( "\n" ); document.write( "All you have to do now is to select a value that is NOT an end point from each of the three intervals and find the value of your LHS function at each of those three selected values. You will either get two positive and one negative value(s) or two negative and one positive value(s). In the former case, your desired interval is just the center interval. In the latter case, your desired interval is the union of the two outer intervals. Just use a 'cup' symbol (a big 'U' or ) to indicate union\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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