document.write( "Question 497688: using the infinite series equation, explain how .9 repeating equals one. I tried to do it by myself, but I cannot figure it out. Please help me, but not give me a direct answer. \n" ); document.write( "
Algebra.Com's Answer #414656 by Evy Hofbauer(7)![]() ![]() You can put this solution on YOUR website! 1/3 times 3 is equal to both so using equations,\r \n" ); document.write( "\n" ); document.write( "1/3(3)=1/3(3)\r \n" ); document.write( "\n" ); document.write( ".9 repeated =1/3(3) \n" ); document.write( "1= 1/3(3)\r \n" ); document.write( "\n" ); document.write( ".9 repeated = 1\r \n" ); document.write( "\n" ); document.write( "The infinite series equation for this... \n" ); document.write( "so .9 is 9/10 \n" ); document.write( ".99 is 99/100 \n" ); document.write( ".999 is 999/1000 \n" ); document.write( ".9999 is .9999/10000 \n" ); document.write( "You can see where is am going with this... \n" ); document.write( "if not keep scrolling.. \n" ); document.write( ".9 + .09 + .009 + .0009 = .9999 \n" ); document.write( ".09 = 9/100 \n" ); document.write( ".009 = 9/1000 \n" ); document.write( ".0009 = 9/10000 \n" ); document.write( "so you are essentially adding \n" ); document.write( "9/10 + 9/100 + 9/1000 +9/10000 \n" ); document.write( "So the geometric series version is...\r \n" ); document.write( "\n" ); document.write( "sum ( 9/(10)^n , n, 1, forever) and..... = 1 \n" ); document.write( " |