document.write( "Question 60370: Geometry. \r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 2 in. more than twice its width. If the
\n" ); document.write( "perimeter of the rectangle is 34 in., find the dimensions of the rectangle.
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Algebra.Com's Answer #41464 by checkley71(8403)\"\" \"About 
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L=2+2W
\n" ); document.write( "2L+2W=34
\n" ); document.write( "2(2+2W)+2W=34
\n" ); document.write( "4+4W+2W=34
\n" ); document.write( "6W=34-4
\n" ); document.write( "6W=30
\n" ); document.write( "W=30/6
\n" ); document.write( "W=5
\n" ); document.write( "THEN L=2+2*5
\n" ); document.write( "L=2+10
\n" ); document.write( "L=12
\n" ); document.write( "PROOF
\n" ); document.write( "2*5+2*12=34
\n" ); document.write( "10+24=34
\n" ); document.write( "34=34
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