document.write( "Question 666659: How would you find x on an isoceles triangle if the base is 9, and the two congruent sides are 5x^2+9x-10 and 4x^2+5x+11 \n" ); document.write( "
Algebra.Com's Answer #414607 by MathLover1(20855)\"\" \"About 
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the two congruent sides are \"5x%5E2%2B9x-10\" and \"4x%5E2%2B5x%2B11\";\r
\n" ); document.write( "\n" ); document.write( "so if two sides congruent, we have\r
\n" ); document.write( "\n" ); document.write( "\"5x%5E2%2B9x-10=4x%5E2%2B5x%2B11\"....solve for \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2-4x%5E2%2B9x-5x-10-11=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B4x-21=0\".....use quadratic formula\r
\n" ); document.write( "\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" \r
\n" ); document.write( "\n" ); document.write( " \"x+=+%28-4+%2B-+sqrt%28+4%5E2-4%2A1%2A%28-21%29+%29%29%2F%282%2A1%29+\" \r
\n" ); document.write( "\n" ); document.write( " \"x+=+%28-4+%2B-+sqrt%28+16%2B84+%29%29%2F2+\" \r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+sqrt%28100%29%29%2F2+\" \r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+10%29%2F2+\".....since side has to be positive, we will look for positive root only \r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B+10%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+6%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x+=+3%29+\"\r
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