document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=666610>Question 666610</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A certain unfair coin lands on heads 1/3 of the time. The coin is tossed 5 times. Finds the probability of no more than 3 heads\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414574 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414574\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Probability of heads = 1/3<BR>\n" );
document.write( "Probability of tails = 2/3\r<BR>\n" );
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document.write( "P[no more than 3 heads] = 1-P[4 heads or 5 heads] =  1-(P[4 heads] + P[5 heads])\r<BR>\n" );
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document.write( "1 - ((5 choose 4)(1/3)^4*(2/3)^1 + (5 choose 5)(1/3)^5(2/3)^0) = 0.9547 </SPAN>\n" );
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