document.write( "Question 666507: Direction are complete the square.\r
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document.write( "x^2+2x=5\r
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document.write( "Am I suppose to set this to zero? When I do, I don't know what would make the sum of 2 and give me -5.\r
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document.write( "I get to x^2+2x-5=0
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Algebra.Com's Answer #414554 by Leaf W.(135)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "* \n" ); document.write( "No, you are not supposed to set this equal to zero when you complete the square; that is for quadratic formula. It is in perfect starting format the way it is -- the coefficient of \n" ); document.write( "* \n" ); document.write( "Divide the coefficient of the \"x\" term (in this case, the x term would be 2x, so its coefficient would be the number before the x, 2) in half. This would give you \n" ); document.write( "* \n" ); document.write( "Square this number: \n" ); document.write( "* \n" ); document.write( "Add the result to both sides of the equation: \n" ); document.write( "* \n" ); document.write( "Simplify the right side of the equation: \n" ); document.write( "* \n" ); document.write( "Factor the left side of the equation: \n" ); document.write( "* \n" ); document.write( "Square root both sides. Remember that the right side could be either the positive or the negative square root: x + 1 = ± \n" ); document.write( "* \n" ); document.write( "Isolate the x by subtracting 1 from both sides: x = -1 ± \n" ); document.write( "* \n" ); document.write( "Your final answer is x = -1 ± |