document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=666555>Question 666555</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The first of three numbers exceeds twice the second number by 4, while the third number is twice the first. If the sum of the three numbers is 54, find the numbers. \r<BR>\n" );
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document.write( "please help me. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414536 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414536\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> second number be x<BR>\n" );
document.write( "first number = 2x+4\r<BR>\n" );
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document.write( "third number =2(2x+4)\r<BR>\n" );
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document.write( "sum =54\r<BR>\n" );
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document.write( "x+2x+4+2(2x+4)=54\r<BR>\n" );
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document.write( "x+2x+4+4x+8=54<BR>\n" );
document.write( "7x+12=54<BR>\n" );
document.write( "7x=54-12<BR>\n" );
document.write( "7x=42<BR>\n" );
document.write( "x=6\r<BR>\n" );
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document.write( "First number = 6<BR>\n" );
document.write( "second number = 2x+4 ------> 2*6+4 = 16<BR>\n" );
document.write( "Third number = 2*16=32\r<BR>\n" );
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document.write( "6,16,32<BR>\n" );
document.write( "add them up you get 54 </SPAN>\n" );
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