document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=666554>Question 666554</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 36. If the larger is divided by the smaller, the quotient is 2 and the remainder is 3. Find the numbers.\r<BR>\n" );
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document.write( "Please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414534 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414534\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the numbers be x & y x>y\r<BR>\n" );
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document.write( "x+y = 36\r<BR>\n" );
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document.write( "dividend = divisor * quotient + remainder\r<BR>\n" );
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document.write( "x= y*2+3<BR>\n" );
document.write( "x-2y=3\r<BR>\n" );
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document.write( "x+y=36<BR>\n" );
document.write( "x-2y=3\r<BR>\n" );
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document.write( "multiply first equation by 2 and add to the second\r<BR>\n" );
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document.write( "2x+2y=72<BR>\n" );
document.write( "x-2y=3<BR>\n" );
document.write( "3x=75<BR>\n" );
document.write( "/3<BR>\n" );
document.write( "x=25\r<BR>\n" );
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document.write( "plug value of x in <BR>\n" );
document.write( "x+y = 36<BR>\n" );
document.write( "25+y=36<BR>\n" );
document.write( "y=36-25<BR>\n" );
document.write( "y=11\r<BR>\n" );
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document.write( "the numbers are 25 & 11 </SPAN>\n" );
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