document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=666473>Question 666473</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Alberto made a trip to his friends house and back. The trip there took three hours and the trip back took four hours. He averaged 9.8 mph faster on the trip there than on the return trip. Find Alberto's average speed on the outbound trip. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414533 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414533\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the speed on return be x mph : time = 4 hours\r<BR>\n" );
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document.write( "speed going there = x+9.8 mph : Time = 3 hours\r<BR>\n" );
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document.write( "Distance is the same forward and return\r<BR>\n" );
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document.write( "d=rt\r<BR>\n" );
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document.write( "4x= 3(x+9.8)\r<BR>\n" );
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document.write( "4x= 3x+29.4 \r<BR>\n" );
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document.write( "x= 29.4 mph </SPAN>\n" );
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