document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=666515>Question 666515</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a chemist needs 150 mm of a 38% solution but has only 22% and 82% solutions available. Find how many mm of each that should be mixed to get the desired solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414517 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414517\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	percent	----------------			quantity								<BR>\n" );
document.write( "Solution I	22	----------------			x	ml							<BR>\n" );
document.write( "Solution II	82	------	150	-	x	ml							<BR>\n" );
document.write( "Mixture	30	----------------	150										<BR>\n" );
document.write( "													<BR>\n" );
document.write( "22x+82(150-x)=30*150	<BR>\n" );
document.write( "2200x+8200(150-	x)=	450000			<BR>\n" );
document.write( "2200x+1230000-	8200x=	450000			<BR>\n" );
document.write( "2200x-8200x=	450000		-1230000			<BR>\n" );
document.write( "-6000	x			=	-780000								<BR>\n" );
document.write( "/	-6000												<BR>\n" );
document.write( "	x			=	130		ml			22.00%		Solution I	<BR>\n" );
document.write( "					20		ml			82.00%		Solution II	<BR>\n" );
document.write( "													<BR>\n" );
document.write( "m.ananth@hotmail.ca													<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );