document.write( "Question 666452: what is the answer of this questions:
\n" ); document.write( "1.) (-3-3√3)^2
\n" ); document.write( "2.) 5 ÷i
\n" ); document.write( "3.) 1÷(2i-3)
\n" ); document.write( "4.)(3+2i÷(2-i)
\n" ); document.write( "5.) (3+ 2i) ÷ 4
\n" ); document.write( "6.) 1 ÷ ( 3+ √-2) \n" ); document.write( "

Algebra.Com's Answer #414471 by DrBeeee(684) $\"\"$ $\"About$

You can put this solution on YOUR website!
1) (-3-3sqrt(3))^2 = (-3)^2*(1+sqrt(3))^2 = 9*(1+2*sqrt(3) +3) = 18*(2+sqrt(3))
\n" ); document.write( "2) 5/i = 5*i/i*i = 5i/(-1) = -5i
\n" ); document.write( "3) 1/(2i-3) = (2i+3)/((2i-3)*(2i+3)) = (2i+3)/(-4+2i-2i-9) = (2i+3)/(-13) = -3/13 - (2/13)i
\n" ); document.write( "4) 3+(2i)/(2-i) = 3+(2i)(2+i)/(2-i)(2+i) = 3 + 2i(2+i)/5 = 3+(4i-2)/5 = (13+4i)/5 = 13/5 + (4/5)i
\n" ); document.write( "5) (3+2i)/4 = 3/4 + i/2
\n" ); document.write( "6) 1/(3+sqrt(-2)) = 1/(3+i*sqrt(2)) = (3-i*sqrt(2))/((3+i*sqrt(2))*(3-i*sqrt(2))) = (3-i*sqrt(2))/(9+2) = 3/11 - i*(sqrt(2))/11 \n" ); document.write( "

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