document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=666442>Question 666442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> for five algebra examinations, maria has an average of 88. what must she score on the sixth test to bring her average up exactly 90 ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414462 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414462\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use A = sum/6 = 90<BR>\n" );
document.write( "The sum of first 5 is 5*88.<BR>\n" );
document.write( "Let x = score required on sixth test.<BR>\n" );
document.write( "The new sum will be 5*88 + x<BR>\n" );
document.write( "The new average is new sum divided by or<BR>\n" );
document.write( "(1) 90 = (5*88+x)/6 or<BR>\n" );
document.write( "(2) 540 = 5*88 + x or<BR>\n" );
document.write( "(3) x = 540 - 440<BR>\n" );
document.write( "(4) x = 100<BR>\n" );
document.write( "Answer: Maria must get 100 on the sixth exam to obtain a 90 average.<BR>\n" );
document.write( "I feel bad for Maria, but at least she don't need more than 100! </SPAN>\n" );
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