document.write( "Question 60148This question is from textbook Intermediate Algebra
\n" ); document.write( ": I am confused on how to do these kind of problems. The same with chapter 3 Section 3 I am not sure how to solve using substitution and eliminations \n" ); document.write( "
Algebra.Com's Answer #41446 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
X+7Y=10
\n" ); document.write( "-6X+8Y=-10
\n" ); document.write( "USING THE SUBSTITUTION METHOD SOLVE ONE OF THE EQUATIONS FOR X OR Y
\n" ); document.write( "X=10-7Y NOW SUBSTITUTE (10-7Y) FOR X IN THE OTHER EQUATION
\n" ); document.write( "-6(10-7Y)+8Y=-10
\n" ); document.write( "-60+42Y+8Y=-10
\n" ); document.write( "50Y=60=10
\n" ); document.write( "50Y=50
\n" ); document.write( "Y=50/50
\n" ); document.write( "Y=1 NOW SUBSTITUTE 1 FOR Y IN EQUATION 1 WE GET
\n" ); document.write( "X+7*1=10
\n" ); document.write( "X+7=10
\n" ); document.write( "X=10-7
\n" ); document.write( "X=3
\n" ); document.write( "NOW FOR THE ELIMINATION METHOD USING THE SAME EQUATIONS
\n" ); document.write( "X+7Y=10
\n" ); document.write( "-6X+8Y=-10 NOW WE MULTIPLY EQUATION 1 BY 6 WE GET
\n" ); document.write( "6X+42Y=60 NOW ADD THESE TWO EQUATIONS
\n" ); document.write( "----------------------
\n" ); document.write( "0X+50Y=50
\n" ); document.write( "50Y=50
\n" ); document.write( "Y=50/50
\n" ); document.write( "Y=1 NOW SUBSTITUTE I FOR Y IN EITHER EQUATION WE GET
\n" ); document.write( "-6X+8*1=-10
\n" ); document.write( "-6X+8=-10
\n" ); document.write( "-6X=-10-8
\n" ); document.write( "-6X=-18
\n" ); document.write( "X=-18/-6
\n" ); document.write( "X=3
\n" ); document.write( "HOPE THIS HELPS :)\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );