document.write( "Question 666400: find the slope and y intercept of the line y=4\r
\n" ); document.write( "\n" ); document.write( "find an equation of a line satisfying the given coditions
\n" ); document.write( "perpendicular to x=7, passing through (-5,4)
\n" ); document.write( "

Algebra.Com's Answer #414451 by DrBeeee(684)\"\" \"About 
You can put this solution on YOUR website!
The slope-intercept form of a line is
\n" ); document.write( "(1) y = m*x + b, where m, the coefficient of x, is equal to the slope, and b is where the line crosses the y-axis, called the y intercept.
\n" ); document.write( "The equation of your line is
\n" ); document.write( "(2) y = 4
\n" ); document.write( "Writing your line in the form of (1) we get
\n" ); document.write( "(3) y = 0*x + 4, where I show that the coefficient of x is zero because you do not have an x-term. Comparing (3) to (1) we have m = 0, which means that the slope of your line, which is equal to m, is ZERO. It is a line parallel to the x-axis that crosses the y-axis at y = 4. Thus the y-intercept of your line, equal to b, is 4.
\n" ); document.write( "Your second line is a vertical line, parallel to the y-axis, crossing the x-axis at x = 7. A line perpendicular to a vertical line is a horizontal line (just like your first one). As such it has a slope equal to 0. Since it must go through the point (-5,4), you tell me what the y-intercept is! You're right it is 4. This line is the same as your first line
\n" ); document.write( "(4) y = 0*x + 4 or
\n" ); document.write( "(5) y = 4
\n" ); document.write( "Note that the horizontal line y = 4 does not depend on the value of x, y is always 4 no matter what x is. You would get the same answer if the line had to go through the point (any number,4)
\n" ); document.write( "I hope I didn't confuse you. Good luck in seeing the big picture of what a line is. It's really not too hard, hang in there.
\n" ); document.write( "
\n" );