document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=666217>Question 666217</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If x = -3, what is the value of\r<BR>\n" );
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document.write( "x to the 7 power -1<BR>\n" );
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document.write( "x   +    1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414343 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414343\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I assume you mean<BR>\n" );
document.write( "(1) ((x^7) - 1)/(x+1)<BR>\n" );
document.write( "and you want to know what this is when x = -3. OK?<BR>\n" );
document.write( "Put x = -3 into (1) and we get<BR>\n" );
document.write( "(2) ((-3)^7 - 1)/(-3+1)<BR>\n" );
document.write( "Now you probable use your calculator to get (-3)^7, and you get an error, right? Sorry you can't do that, ie get a power of a negative number! You can multiply (-3) time itself 7 times or recognize that a negative number raised to an ODD power is negative!<BR>\n" );
document.write( "Then (-3)^7 = -(3)^7, which you can do on your calculator to get -2187. Now continue evaluating (2) and get<BR>\n" );
document.write( "(3) (-2187-1)/(-2) or<BR>\n" );
document.write( "(4) (-2188)/(-2) or<BR>\n" );
document.write( "(5) 1094<BR>\n" );
document.write( "Answer: The value is 1094 </SPAN>\n" );
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