document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=666198>Question 666198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the longest side of a triangle is twice the length of the shortest side.The third side is four inches shorter than the longest side. Find the lengths of the sides of the triangle if the perimeter is 96 inches. Can you please help me write an equation for this problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414336 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a,b,c be the sides in increasing length.\r<BR>\n" );
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document.write( "a+b+c = 96 since the perimeter is 96.\r<BR>\n" );
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document.write( "c = 2a\r<BR>\n" );
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document.write( "and b = c-4\r<BR>\n" );
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document.write( "a = c/2\r<BR>\n" );
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document.write( "b = c-4\r<BR>\n" );
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document.write( "c = c\r<BR>\n" );
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document.write( "c/2 + c-4 + c = 96\r<BR>\n" );
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document.write( "c + 2c-8 +2c = 192  (getting rid of the fraction)\r<BR>\n" );
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document.write( "5c -8 = 192\r<BR>\n" );
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document.write( "5c = 200\r<BR>\n" );
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document.write( "c = 40\r<BR>\n" );
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document.write( "a = c/2 so  a = 20\r<BR>\n" );
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document.write( "b = c-4 so c = 36\r<BR>\n" );
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document.write( "The sides are 20,36,40, which if you notice add up to 96. </SPAN>\n" );
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