document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60293>Question 60293</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534490247/algebrahomeworkh>Elementary and Intermediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> This word problem has to do with coins, but I need to solve it by setting up and solving a system of two linear equations in two variables.\r<BR>\n" );
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document.write( "Cindy has 43 coins consisting of nickels and dimes.  The total value of the coins is $3.40.  How many coins of each kind does she have?\r<BR>\n" );
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document.write( "I have gotten this far:<BR>\n" );
document.write( "n + d = 3.40<BR>\n" );
document.write( "is that right? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41433 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41433\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Er...not quite!<BR>\n" );
document.write( "Let n = the number of nickels ($0.05) and d = the number of dimes ($0.10).<BR>\n" );
document.write( "The sum of the nickels and dimes (coins) can be written:<BR>\n" );
document.write( "1) n + d = 43<BR>\n" );
document.write( "The total value of the coins can be written:<BR>\n" );
document.write( "2) n($0.05) + d($0.10) = $3.40\r<BR>\n" );
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document.write( "This is the required system of two equations in two unknowns (n and d).\r<BR>\n" );
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document.write( "You can solve this system by substitution.<BR>\n" );
document.write( "Solve equation 1) for n: (n = 43 - d) and substitute this into equation 2) then solve for d.\r<BR>\n" );
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document.write( "2a) (43-d)($0.05) + d($0.10) = $3.40 Simplify and solve for d.<BR>\n" );
document.write( "2.15 - 0.05d + 0.10d = 3.40<BR>\n" );
document.write( "2.15 + 0.05d = 3.40 Subtract 2.15 from both sides.<BR>\n" );
document.write( "0.05d = 1.25 Divide both sides by 0.05<BR>\n" );
document.write( "d = 25 There are 25 dimes.<BR>\n" );
document.write( "n = 43 - d<BR>\n" );
document.write( "n = 43 - 25<BR>\n" );
document.write( "n = 18 There are 18 nickels.\r<BR>\n" );
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document.write( "Check:\r<BR>\n" );
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document.write( "n + d = 18 + 25 = 43\r<BR>\n" );
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document.write( "18($0.05) + 25($0.10) = $0.90 + $2.50 = $3.40 </SPAN>\n" );
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