document.write( "Question 666142: The width of a rectangular painting is 2 inches less than the length. The area is 120 inches squared. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #414299 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
w = l-2\r
\n" ); document.write( "\n" ); document.write( "l * l-2 = 120\r
\n" ); document.write( "\n" ); document.write( "l^2 - 2l = 120\r
\n" ); document.write( "\n" ); document.write( "l^2 - 2l -120 = 0\r
\n" ); document.write( "\n" ); document.write( "(l-12)(l+10) = 0\r
\n" ); document.write( "\n" ); document.write( "l = 12 l =-10\r
\n" ); document.write( "\n" ); document.write( "Length can't be negative so l = 12.\r
\n" ); document.write( "\n" ); document.write( "Then w = 12 -2 = 10\r
\n" ); document.write( "\n" ); document.write( "12 x 10.
\n" ); document.write( "
\n" );