document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=666127>Question 666127</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a company that replicates DVDs spends $1500 per day in building overhead plus $0.80 per DVD in supplies and labor. If the DVDs sell for $1.59 per disk, how many DVDs must the company sell each day before it makes a profit? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414278 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414278\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let d be the number DVDs per day.\r<BR>\n" );
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document.write( "Then let E be the expenses where E= 1500 + .80d\r<BR>\n" );
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document.write( "And let R be the revenue where R = 1.59d.\r<BR>\n" );
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document.write( "Find d such that R > E.\r<BR>\n" );
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document.write( "So  1.59d > 1500+.80d\r<BR>\n" );
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document.write( "Subtract .80d on both sides:\r<BR>\n" );
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document.write( ".79d > 1500\r<BR>\n" );
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document.write( "d > 1898.734\r<BR>\n" );
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document.write( "We can only sell an integer amount of DVDs, so we must sell 1899 DVDs a day to make a profit. </SPAN>\n" );
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