document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=665984>Question 665984</A>: <I><SPAN STYLE=\"word-break: break-all;\"> : The width of a rectangle is 5cm less than its length. If its perimeter is 38cm, find its width.. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414192 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given<BR>\n" );
document.write( "w = l-5; rearrange as l = w+5<BR>\n" );
document.write( "p = 38<BR>\n" );
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document.write( "Knowing<BR>\n" );
document.write( "p = 2l + 2w<BR>\n" );
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document.write( "Substitute into the perimeter equation and solve for w<BR>\n" );
document.write( "2(w+5) + 2w = 38<BR>\n" );
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document.write( "Distribute the 2<BR>\n" );
document.write( "2w + 10 + 2w = 38<BR>\n" );
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document.write( "Combine like terms<BR>\n" );
document.write( "4w = 38 - 10<BR>\n" );
document.write( "4w = 28<BR>\n" );
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document.write( "Divide both sides by 4<BR>\n" );
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