document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=665886>Question 665886</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve (x-2)^2-2=-x+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414141 by </B><A HREF=/tutors/aboutme.mpl?userid=Jacky+C><B>Jacky C(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jacky+C><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414141\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in the exponents 2-2 is equal to 0 so\r<BR>\n" );
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document.write( "(x - 2)^0 = -x + 3 \r<BR>\n" );
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document.write( "since -x contains the variable to solve move it for the lefth hand side of the equation by adding x both sides\r<BR>\n" );
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document.write( "(x - 2)^0 +x = 3\r<BR>\n" );
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document.write( "anything raised to the 0th power is 1\r<BR>\n" );
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document.write( "(1)+ x = 3\r<BR>\n" );
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document.write( "reorder the polynomial by alphabetically from the left to right\r<BR>\n" );
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document.write( "x + 1 = 3    \r<BR>\n" );
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document.write( "so 1 don't have the variable to solve the move them from the right hand\r<BR>\n" );
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document.write( "x= -1 + 3 solve\r<BR>\n" );
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document.write( "the answer is x=2\r<BR>\n" );
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