document.write( "Question 665756: If both the numerator and the denominator of a certain fraction are increased by 1, it becomes 5/6.if both the numerator and denominator are each decreased by 1 it becomes 4/5.find the original fraction \n" ); document.write( "
Algebra.Com's Answer #414116 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! If both the numerator and the denominator of a certain fraction are increased by \n" ); document.write( " 1, it becomes 5/6.if both the numerator and denominator are each decreased by 1 \n" ); document.write( " it becomes 4/5.find the original fraction \n" ); document.write( ": \n" ); document.write( "\"If both the numerator and the denominator of a certain fraction are increased by 1, it becomes 5/6.\" \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "6(n+1) = 5(d+1) \n" ); document.write( "6n + 6 = 5d + 5 \n" ); document.write( "6n - 5d = 5 - 6 \n" ); document.write( "6n - 5d = -1 \n" ); document.write( ": \n" ); document.write( "\" both the numerator and denominator are each decreased by 1 it becomes 4/5.\" \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "5(n-1) = 4(d-1) \n" ); document.write( "5n - 5 = 4d - 4 \n" ); document.write( "5n - 4d = -4 + 5 \n" ); document.write( "5n - 4d = 1 \n" ); document.write( ": \n" ); document.write( "We can use elimination here, Mult the 1st eq by 4, mult the 2nd eq by 5 \n" ); document.write( "Subtract the 1st equation from the 2nd equation \n" ); document.write( "25n - 20d = 5 \n" ); document.write( "24n - 20d = -4 \n" ); document.write( "--------------- Subtraction eliminates d, find n \n" ); document.write( "n = 9 \n" ); document.write( ": \n" ); document.write( "find d using 5n - 4d = 1 \n" ); document.write( "5(9) - 4d = 1 \n" ); document.write( "45 - 4d = 1 \n" ); document.write( "-4d = 1 - 45 \n" ); document.write( "-4d = 44 \n" ); document.write( "d = +11 \n" ); document.write( ": \n" ); document.write( " |