document.write( "Question 665845: 4/r+9-4r/3r=r/3 \n" ); document.write( "
Algebra.Com's Answer #414113 by pv=nrt15rcks(23)\"\" \"About 
You can put this solution on YOUR website!
\"3r%284%2Fr%2B%289-4r%29%2F3r=r%2F3%29\"
\n" ); document.write( "\"12%2B9-4r=r%5E2\"
\n" ); document.write( "\"21-4r=r%5E2\"
\n" ); document.write( "\"sqrt%2821%2F3%29=r\"
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